Question 975755
You have two square plots formed with 100m of fencing. Determine the equation of the curve of best fit, and use the equation to determine the value of x that minimizes the area of each square.
(Must use quadratics, no derivatives/calculus)
Only thing I've seen to do is {{{A = X^2 + Y^2}}} then {{{100 = 4x + 4y}}}. {{{25=x+y}}}, {{{y=25-x}}}.

{{{A=X^2 + (25-x)^2}}}
{{{A=x^2 + 625 - 25x - 25x + x^2}}} ***************
{{{A=x^2 - 50x + 625}}} **************** {{{A = 2x^2 - 50x + 625}}}
But then solutions for x are imaginary, what do I do now?
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{{{A=2x^2 - 50x + 625}}}
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There are no real zeroes for x, but that's not relevant.
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{{{A=2x^2 - 50x + 625}}}
The minimum of the parabola is the vertex @ x = -b/2a
x = -50/-4 = 12.5 --> minimum Area
Minimum area = 312.5 sq m