Question 975679
 A normally distributed population with 200 elements has a mean of 60 and a standard deviation of 10. The probability that the mean of a sample of 25 elements taken from this population will be smaller than 56 is:
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z(56) = (56-60)/[10/sqrt(25)] = -4/2 = -2
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P(x-bar < 56) = P(z < -2) = normalcdf(-100,-2) = 0.0228
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Cheers,
Stan H.
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Select one:
a. 0.0166. 
b. 0.0228.
c. 0.3708.
d. 0.0394.