Question 975669
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Since the *[tex \Large x]-coordinate of the top and bottom is 5 and the *[tex \Large y]-coordinate of the left and right is 2, the center has to be at *[tex \Large (5,2)].


Since the distance from the center to any one of the given points is 2 (I'll leave this as an exercise for you to verify), the radius of the circle must be 2.


*[tex \LARGE \ \ \ \ \ \ \ \ \ \  (x\ -\ 5)^2\ +\ (y\ -\ 2)^2\ =\ 4]


You can expand the binomials and collect like terms to put this in General Form for yourself.


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it

*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \