<PRE><B>Question 83206</B>
A stone is dropped from the top of a building 240 feet high. It is observed to take 0.20 seconds to go past an office floor-to-ceiling window that is 12 feet high. How far is it from the bottom of the window down to the street?
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S(t) = -16t^2+240
Velocity = -32t ft/sec
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Velocity of the stone while passing the window:
-12ft/0.2 sec = -60 ft/sec
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Therefore:
-32t =-60 
t= 1.875 seconds
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So, where is the stone at t=1.875 sec ?
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s(1.875) = -32(1.875)^2+240
s(1.875) = 127.5 ft above the ground
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Cheers,
Stan H.</PRE>