Question 975492
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If the perimeter is 60 and the hypotenuse is 26, then the sum of the other two sides must be 34.  Let *[tex \Large x] represent the measure of one of the two legs and then *[tex \Large 34\ -\ x] will represent the measure of the other leg, allowing us to state the pythagorean relationship:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \  x^2\ +\ (34\ -\ x)^2\ =\ 676]


Expand, collect like terms, put the quadratic in standard form, and solve (hint: it factors).  The two roots of the equation represent the measures of the two legs of the triangle.  The area of a right triangle is the product of the legs divided by 2.


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it

*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \