Question 975492
x, y, h for the two legs and the Hypotenuse.


{{{system(x+y+h=60,x^2+y^2=h^2)}}} and h is given.


{{{system(x+y+26=60,x^2+y^2=(26)^2)}}}


{{{system(x+y=36,x^2+y^2=676)}}}


{{{x^2+(36-x)^2=676}}}


{{{x^2+36^2-72x+x^2-676=0}}}


{{{2x^2-72x+1296-676=0}}}


{{{2x^2-72x+620=0}}}


{{{x^2-36x+310=0}}}


{{{x=(36+- sqrt(56))/2}}}


{{{x=(36+- 2*sqrt(14))/2}}}


{{{highlight(x=18+- sqrt(14))}}}


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Dimensions are  {{{highlight(18-sqrt(14))}}} and {{{36-(18-sqrt(14))=highlight(18+sqrt(14))}}}.