Question 975482
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Yes, the argument is invalid.  It is of the form:


*[tex \LARGE P\ \supset\ Q]


*[tex \LARGE \neg P]


*[tex \LARGE .^{\ .}.\ \neg Q]


In a conditional statement, a false antecedent tells you nothing about the truth of the consequent.


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it

*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \