Question 975451
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*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x\ +\ y\ =\ 60]


But


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x\ =\ \frac{2}{3}y]


So


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \frac{2}{3}y\ +\ y\ =\ 60]


Solve for *[tex \Large y] and then calculate *[tex \Large\ \frac{2}{3}y] to get the value of *[tex \Large x]


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it

*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \