Question 83193
time=distance/rate
seeing as the times are the same we have the following equation:
15/(20-c)=25/(20+c) c=current. now cross multiply.
15(20+c)=25(20-c)
300+15c=500-25c
15c+25c=500-300
40c=200
c=200/40
c=5 rate of the current.
proof
15/(20-5)=25/(20+5)
15/15=25/25
1=1