Question 82965
Divide the following fractions:
:
{{{((6p-18))/(9p)}}}
------------
{{{((3p-q))/((p^2+ 2p))}}}
:
remember when you divide fractions, "Invert the dividing fraction and multiply".
{{{((6p-18))/(9p)}}} * {{{((p^2 + 2p))/((3p - q))}}}
:
Factor
{{{(6(p-3))/(9p)}}} * {{{(p(p + 2))/((3p - q))}}}
:
Cancel 3 into 6 and 9 and p:
{{{(2(p-3))/3}}} * {{{((p + 2))/((3p - q))}}} = {{{(2(p-3)(p+2))/(3(3p-q))}}}; about all you can do with it