Question 975277
1/(x-1)+2 /(x+1)=2
Simplifying we get,
[x+1+2(x-1)]/(x^2-1)=2
3x-1=2x^2-2
2x^2-3x-1=0
*[invoke quadratic "x", 2, -3, -1 ]
x=1.78 or x=-0.28