Question 975228
Find the eccentricity of the graph whose equation is 
14x2 + 16y2 = 224.
divide by 224:
{{{x^2/16+y^2/14=1}}}
This is an equation of an ellipse with horizontal major axis and center at the origin.
Its standard form of equation: {{{(x-h)^2/a^2+(y-k)^2/b^2=1}}}, a>b, (h,k)= coordinates of center
For given equation:
a^2=16 
a=4
b^2=14
c^2=a^2-b^2=16-14=2
c=√2
eccentricity=c/a=√2/4