Question 975203
solve 2ln(x+1)=ln(x^2-1)+ln5
--------------
ln(x+1)^2 = ln[5(x^2-1)]
-----------------
(x+1)^2 = 5x^2 - 5
-------
x^2 + 2x + 1 = 5x^2 - 5
4x^2 - 2x - 6 = 0
------
2x^2 - x - 3 = 0
-----
Factor:
(2x-3)(x+1) = 0
----
Positive solution:
x = 3/2
-------
Cheers,
Stan H.
--------