Question 975181

if {{{f(x)=x^2}}}, then inverse {{{f^(-1)(x)}}} will be:

{{{f(x)=x^2}}}.......recall that {{{f(x)=y}}}, so we have

{{{y=x^2}}}...........swap {{{x}}} and {{{y}}}

{{{x=y^2}}}.......solve for {{{y}}}

{{{y= sqrt(x)}}}, your inverse {{{f^(-1)(x)}}}

{{{f^(-1)(x) = sqrt(x)}}}


so, your answer is: (A) {{{f^(-1)(x) = sqrt(x)}}}