Question 975174
Area of the square, {{{9x^2}}}.
Area of the rectangle, {{{2x(x+7)=2x^2+14x}}}.


{{{9x^2=2(2x^2+14x)}}}.
Solve this for x,... and you can then use it to evaluate the dimensions of these figures.



{{{9x^2=4x^2+28x}}}
{{{5x^2-28x=0}}}
{{{x(5x-28)=0}}}
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Zeros are 0 and 28/5.  The meaningful value is {{{28/5=highlight_green(5&3/5)}}}.


Rectangle Dimensions:
{{{2(28/5)=56/5=highlight(11&1/5)}}}  and  {{{28/5+7=28/5+35/5=63/5=highlight(12&3/5)}}}.