Question 975114
Try using v=x^2 and first solve for v.


{{{15v^2-11v+2=0}}}
If factorable, then easier to finish:


{{{(3v-1)(5v-2)=0}}}


ZERO PRODUCT RULE & REVERSE SUBSTITUION:

{{{3v-1=0}}}
{{{3v=1}}}
{{{v=1/3}}}
{{{x^2=1/3}}}
{{{x=0+- sqrt(1/3)}}}
{{{highlight(x=0+- sqrt(3)/3)}}}


{{{5v-2=0}}}
{{{5v=2}}}
{{{v=2/5}}}
{{{x^2=2/5}}}
{{{x^2=(2/5)(5/5)=10/5^2}}}
{{{highlight(x=0+- sqrt(10)/5)}}}