Question 975116
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B could be any of *[tex \Large \emptyset], *[tex \Large \{m\}], *[tex \Large \{n\}], *[tex \Large \{o\}], *[tex \Large \{p\}], *[tex \Large \{m,n\}],*[tex \Large \{m,o\}],*[tex \Large \{m,p\}],*[tex \Large \{n,o\}],*[tex \Large \{n,p\}],*[tex \Large \{o,p\}],*[tex \Large \{m,n,o\}],*[tex \Large \{m,o,p\}],*[tex \Large \{m,n,p\}],*[tex \Large \{n,o,p\}], or *[tex \Large \{m,n,o,p\}].


In general, a set with *[tex \Large n] elements has *[tex \Large 2^n] subsets.


You can't define C until you have defined B.


Regardless, if C is indeed a subset of B, then C is a subset of A given that B is a subset of A.


In general if *[tex \Large S_2\ \subseteq\ S_1] and *[tex \Large S_3\ \subseteq\ S_2] then *[tex \Large S_3\ \subseteq\ S_1]


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it

*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \