Question 975106


{{{(x^2+2x)^(1/3)=2}}}

{{{root(3,(x^2+2x))=2}}}

{{{(root(3,(x^2+2x)))^3=2^3}}}

{{{x^2+2x=8}}}

{{{x^2+2x-8=0}}}

{{{x^2+4x-2x-8 = 0}}}

{{{(x^2+4x)-(2x+8) = 0}}}

{{{x(x+4)-2(x+4) = 0}}}

{{{(x-2)(x+4) = 0}}}


solutions:

if {{{(x-2) = 0}}}=>{{{highlight(x=2)}}}

if {{{(x+4) = 0}}}=> {{{highlight(x=-4)}}}