Question 975020


Let n = 1, 2, 3, 4, 5 


For n = 1:  a_n = 2n-1  --->  a_1 = 2(1) - 1 = 1


For n = 2: a_2 = 2(2) - 1 = 3


For n = 3:  a_3 = 2(3) - 1 = 5


For n = 4: a_4 = 2(4) - 1 = 7


For n = 5: a_5 = 2(5) - 1 = 9


The first five terms of the sequence is 1, 3, 5, 7, 9.