Question 975040
Find secθ if tanθ = 0.6, and θ is not in the first quadrant
-------------------
tan = y/x = 0.6 = 3/5
{{{r = sqrt(x^2 + y^2) = sqrt(34)}}}
----
|sec| = r/x = sqrt(34)/5
------
tangent is positive in Q1 and Q3
sec is negative in Q3
--> {{{sec(theta) = -sqrt(34)/5}}}