Question 974931
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Since she is replacing the name, the two events are independent.  The probability of drawing a table A student on the second draw is exactly the same as the probability of drawing a table A student on the first draw.


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it

*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \