Question 974978
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Let *[tex \Large x] represent the measure of the first angle.  The second angle, being 3 times as large as the first, must measure *[tex \Large 3x].  The third angle, being twice as large as the second angle, must measure *[tex \Large 6x].  The sum of the angles of any triangle is 180 degrees, hence:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x\ +\ 3x\ +\ 6x\ =\ 180]


Solve for *[tex \Large x], then compute *[tex \Large 3x] and *[tex \Large 6x].


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it

*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \