Question 83162
{{{x + 1/x = 3/x + 3}}}
You can make it into a quadratic equation by multiplying each term by x (to get rid of the x's in the denominators)
{{{x^2 + 1= 3 + 3x}}}
Now rearrange:
{{{x^2-3x-2=0}}}
And use the quadratic formula to solve:
{{{x= (3+-sqrt(3^2-4*-2))/2}}}
Which gives:
x=3.56 or x=-0.56