Question 974947
mean is 65%

1 sample proportion z-test; 
phat-0.65/sqrt[[(0.65)*(0.35)/70}; phat = 0.714
z=(0.714-0.65)/.0570
z=+1.123  the probability that 50 or LESS will.  This is 0.870
The probability that at least 50 will is 0.130.

This makes intuitive sense.  The expected value if 45.5, so the likelihood of at least 50 in a sample will is less than half.