Question 83158
{{{2x+6=8+sqrt(5x+1)}}}
Subtract 8 from both sides:
{{{2x-2=sqrt(5x+1)}}}
Now square both sides:
{{{(2x-2)^2=5x+1}}}
Expanding the bracket:
{{{4x^2-8x+4=5x+1}}}
Rearrange:
{{{4x^2-13x+3=0}}}
Now factorise:
{{{(4x-1)(x-3)=0}}}
This gives:
x={{{1/4}}} or x=3