Question 974837
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Oddly enough, East and South differ by 90 degrees, hence consider the following three points: Where the two airplanes originated, the location of the first airplane at any time greater than zero, and the location of the second airplane at that same time.  These three points are the vertices of a right triangle.  One leg of the triangle, recalling that distance equals rate times time, is 550t for any time t > 0.  The other leg measures 600t.  And the distance between the two aircraft is the hypotenuse.


Now if you simply recall what Mr. Pythagoras taught us, you should be able to write an expression that is equal to d(t), the measure of the hypotenuse at time t. 


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it

*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \