Question 974736
I will solve number 2.


Repost number 1 for someone else to solve.


Solve for x: x+3/12 = 6/x-3


Cross-multiply to remove fractions.


(12)(6) = (x+3)(x-3)


72 = x^2 - 9


0 = x^2 -9 -72


0 = x^2 - 81


0 = (x-9)(x+9)


Set each factor to equal zero and Solve


individually for x.

x-9 = 0

x = 9


Then x + 9 = 0.


x + 9 = 0

x = -9


The values of x are -9 and 9.