Question 974701
Find the exact values of the six trigonometric functions of angle theta if sec theta = -5 and (pie/2) < theta < pie
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Reference angle theta is in quadrant II where sin>0, cos<0
sec theta=-5
cos theta=-1/5
sin theta=&#8730;(1-cos ^2 theta)=&#8730;(1-(1/25))=&#8730;24/5
csc theta=5/&#8730;24=(5&#8730;24)/24
tan theta=sin theta/cos theta=-&#8730;24
cot theta=-1/&#8730;24=-&#8730;24/24