Question 974686
{{{x^2 + y^2 + 8x − 10y − 40 = 0}}}
{{{x^2+8x+y^2-10y=40}}}
{{{x^2+8x+16+y^2-10y+25=40+16+25}}}
{{{(x+4)^2+(y-5)^2=81}}}
It's a circle centered at (-4,5) with a radius of 9.