Question 974620

How to simplify:
{3^{n+2} - 3^n + 15{3^{n-1}} }/39
<pre>{{{(3^(n + 2) - 3^n + 15(3^(n - 1)))/39}}}
{{{(3^(n - 1) * (3^3 - 3^1 + 15))/39}}} ------- Factoring out GCF, {{{3^(n - 1)}}} in numerator
{{{(3^(n - 1)*(27 - 3 + 15))/39}}}
{{{(3^(n - 1)*(39))/39}}}
{{{(3^(n - 1)*cross((39)))/cross(39)}}}_______{{{highlight_green(3^(n - 1))}}}