Question 974559

I have to find any Extraneous solution for this rational equation 3x divided by x+1 = to 2x-1 divided by x+1
<pre>{{{3x/(x + 1) = (2x - 1)/(x + 1)}}}, with {{{x <> - 1}}}
3x = 2x - 1 ------- Setting numerators equal to each other since denominators are the same
3x - 2x = - 1
x = - 1, but {{{x <> - 1}}}, so {{{highlight_green(x = - 1)}}} is an EXTRANEOUS SOLUTION.