Question 83098
To find the inverse of the given function. 


f(x) = {{{(x^(1/3)) + 2}}} 


Let y =  f(x) = {{{(x^(1/3)) + 2}}}  



y = {{{(x^(1/3)) + 2}}}  


Replacing x and y we get: 


x = {{{(y^(1/3)) + 2}}}  


Solving for y, further we get: 


x - 2  =  {{{(y^(1/3))}}} 


Taking the cube root on both sides, we get: 


y = {{{(x - 2)^3}}} 


Thus, the inverse value is: 


{{{(f^-1 (x))}}} = {{{(x - 2)^3}}}



Hence, the solution.. 



Happy Calculating!!