Question 974545
The other complex zero is -2-3i.  Together, these two give the quadratic factor,  {{{(x-(-2+3i))(x-(-2-3i))}}}
{{{(x+2-3i)(x+2+3i)}}}
{{{((x+2)-3i)((x+2)+3i)}}}
{{{(x+2)^2+9}}}
{{{x^2+4x+4+9}}}
{{{x^2+4x+13}}}


Divide the given cubic expression or function by {{{x^2+4x+13}}}.  Use polynomial division if necessary.  I am not showing that work here, but the quotient will be <b>x-1</b>.  The zero for this is  +1.