Question 974349


Let P = probability = 60%, R1 = airline reservation of first member and R2 = airline reservation of second member.


Probability that first member made an airline reservation last year is .60, or P(R1)  = .60


Probability second member made a reservation is .60, therefore  P(R2) = .60


Since both members were selected randomly, we assume they are independent meaning one has no effect on the probability of the other, 


P(R1 and R2) =  P(R1)* P(R2) = (.60)*(.60) = .36


Therefore, the probability (P) that both made airline reservations last year is .36 or 36%.