Question 974400
First Draw:


There are 5 yellow labs out of 3+5+2 = 10 labs total. 


P(yellow lab) = 5/10 = 1/2



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Second Draw:


We don't put the lab back, so this is considered without replacement. There are 10-1 = 9 labs left after drawing a yellow lab. There are 5-1 = 4 yellow labs left.


There are (4 yellow)+(2 chocolate) = 6 labs that we want on the second draw out of 9 labs total leftover



P(yellow or chocolate on second draw) = 6/9 = 2/3



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Multiply the two probabilities: (1/2)*(2/3) = (1*2)/(2*3) = 2/6 = <font color="red">1/3</font>



Final Answer: <font size=5 color="red">1/3</font>


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