Question 974358
Perpendicular lines have slopes that are negative reciprocal.
{{{(1/5)*m[2]=-1}}}
{{{m[2]=-5}}}
Then using the point-slope form,
{{{y-(-3)=-5(x-2)}}}
{{{y+3=-5x+10}}}
{{{y=-5x+7}}}
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*[illustration va7.JPG].