Question 974322
Solve for x algebraically: ((e^x)-(e^-x))/2=5
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{{{e^x - e^(-x) = 10}}}
Multiply by e^x
{{{e^(2x) - 1 = 10e^x}}}
{{{e^(2x) - 10e^x - 1 = 0}}}
Sub u for e^x
{{{u^2 - 10u - 1 = 0}}}
*[invoke solve_quadratic_equation 1,-10,-1]
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The answer matches.