Question 974250
Graph the equation to solve the system::
 problem one y=1/3x+1 and y=-1/2x-4.
Substitute and solve for "x"
(1/3)x+1 = (-1/2)x-4
[(1/3)+(1/2)]x = -5
(5/6)x = -5
x = -6
---
Solve for "y"
y = (1/3)x+1
y = (1/3)*-6 + 1
y = -1
-----
{{{graph(400,400,-10,10,-10,10,(1/3)x+1,(-1/2)x-4)}}}
------------------

problem two y=-1/2x and y=-1/3x+1.
Solve for "x":
(-1/2)x = (-1/3)x+1
-------
[(1/3)-(1/2)]x = 1
-1/6 x = 1
x = -6
---
Solve for "y"
y = (-1/2)x
y = 3
---------------
{{{graph(400,400,-10,10,-10,10,(-1/2)x,(-1/3)x+1)}}}
------------
Cheers,
Stan H.
----------------------

problem three y=1/3x +2 and y=-1/3x-2.