Question 974238

{{{C[1]+C[2]=0.00027}}}.....eq.1 

{{{C[1]-C[2]=0.0016}}}......eq.2
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{{{C[1]+C[2]=0.00027}}}.....eq.1... solve for {{{C[1]}}}

{{{C[1]=0.00027-C[2]}}}........substitute in eq.2


{{{0.00027-C[2]-C[2]=0.0016}}}......eq.2...solve for {{{C[2]}}}

{{{-2C[2]=0.0016-0.00027}}}

{{{-2C[2]=0.00133}}}

{{{C[2]=0.00133/-2}}}

{{{highlight(C[2]=-0.000665)}}}

now go to {{{C[1]=0.00027-C[2]}}}........substitute {{{C[2]}}} and solve for {{{C[1]}}}

{{{C[1]=0.00027-(-0.000665)}}}

{{{C[1]=0.00027+0.000665}}}

{{{highlight(C[1]=0.000935)}}}


check:

{{{C[1]+C[2]=0.00027}}}.....eq.1

{{{0.000935-0.000665=0.00027}}}

{{{0.00027=0.00027}}}