Question 974221
(a) 


Given:
*[Tex \LARGE n_1 = 40]
*[Tex \LARGE \hat{p}_1 = 0.4]
*[Tex \LARGE n_2 = 40]
*[Tex \LARGE \hat{p}_2 = 0.4]


Use the given values to compute the following


*[Tex \LARGE s_{d} = \sqrt{\frac{\hat{p}_1*(1-\hat{p}_1)}{n_1}+\frac{\hat{p}_2*(1-\hat{p}_2)}{n_2}}]


*[Tex \LARGE s_{d} = \sqrt{\frac{0.4*(1-0.4)}{40}+\frac{0.4*(1-0.4)}{40}}]


*[Tex \LARGE s_{d} \approx 0.1095445115]


*[Tex \LARGE s_{d} \approx 0.110]


Answer: <font color="red">0.110</font>


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(b)


Given:
*[Tex \LARGE n_1 = 34]
*[Tex \LARGE \hat{p}_1 = 0.6]
*[Tex \LARGE n_2 = 38]
*[Tex \LARGE \hat{p}_2 = 0.67]


Use the given values to compute the following


*[Tex \LARGE s_{d} = \sqrt{\frac{\hat{p}_1*(1-\hat{p}_1)}{n_1}+\frac{\hat{p}_2*(1-\hat{p}_2)}{n_2}}]


*[Tex \LARGE s_{d} = \sqrt{\frac{0.6*(1-0.6)}{34}+\frac{0.67*(1-0.67)}{38}}]


*[Tex \LARGE s_{d} \approx 0.1134779475]


*[Tex \LARGE s_{d} \approx 0.113]


Answer: <font color="red">0.113</font>

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