Question 974199
A box contains nickels, dimes and pennies worth $6.20. The number of nickels is two less than twice the number of dimes and there is an equal number of pennies and dimes. How many nickels are in the box?
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let x=number of pennies and dimes
2x-2=number of nickels
..
.10x+.01x+.05(2x-2)=6.20
.10x+.01x+.10x-.10=6.20
.21x6.30
x=30
2x-2=58 
How many nickels are in the box? 58