Question 974224
Ho: mu >=7
Ha: mu<7  The hypotheses must encompass the whole density function
a=0.05  1 tail test
Test statistic, t df=9
Critical value t (df=9) < -1.833   ;; (xbar-mu)/s/sqrt(9);; 3 (xbar-mu)/s
t=+0.5916  The mean is >7 (7.15), so the null hypothesis cannot be rejected a priori, since the data themselves show a mean greater than that which was postulated to be the maximum value.
p=0.7157, but this is a calculated value, and again the fact that the mean is not in the range of Ha makes rejecting Ho impossible with this sample.

Note: if it were two-tailed, it still wouldn't be rejected.