Question 83070
-9(x-3)^2=-7 first you must take care of the power term:
(x-3)^2=x^2-6x+9 now multiply this by -9 thus
-9(x^2-6x+9)=9x^2+54x-81 now set this term equal to -7 thus:
9x^2+54x-81=-7 now add 7 from both sides.
9x^2+54x-81+7=-7+7
9x^2+54x-72=0 now factor this quadratic equation by dividing each term by 9:
9(x^2+6x-8)=0 now factor this remaining equation using the quadratic equation:
{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}}
x=(-6+-sqrt[6^2-4*1*-8])/2*1
x=(-6+-sqrt36+32])/2
x=(-6+-sqrt68)/2
x=(-6+-8.246)/2
x=(-6+8.246)/2
x=2.246/2
x=1.123 answer.
x=(-6-8.246)/2
x=-14.246)/2
x=-7.123 answer.