Question 974072
{{{2(log((3))^"")(log((x))^"")}}}{{{"=""}}}{{{log((2))}}}
<pre>
Divide both sides by {{{2log((3))}}}

{{{log((x))}}}{{{"=""}}}{{{log((2))/(2log((3)))}}}

Evaluate the right side with a calculator:


{{{log((x))}}}{{{"=""}}}{{{0.3154648768}}}

Now we remember from the definition of logarithm that the

logarithm equation {{{log(B,(A))}}}{{{""=""}}}{{{C}}} is by definition
equivalent to the exponential equation {{{A}}}{{{""=""}}}{{{B^C}}}.

Also we learned that when no base B is written it is understood that
the base B = 10.  Therefore

{{{log((x))}}}{{{"=""}}}{{{0.3154648768}}}

is equivalent to:

{{{x}}}{{{""=""}}}{{{10^0.3154648768}}}

Using our calculator again we get

{{{x}}}{{{""=""}}}{{{2.06759216}}}

Edwin</pre>