Question 974073
The points on the curve y = x3 - x2 - x + 1, where the tangent is parallel to x-axis are
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Find the 1st derivative:
f'(x) = 3x^2 - 2x - 1
Parallel to the x-axis --> slope = 0 --> f'(x) = 0
3x^2 - 2x - 1 = 0
(3x + 1)*(x - 1) = 0
x = -1/3, x = 1