Question 973865
The point (-4,6) is on the terminal side of (theta) in standard position. What is the cosine of (theta)?
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Hypotenuse of reference right triangle in quadrant II=&#8730;(4^2+6^2)=&#8730;(16+36)=&#8730;52
cos(theta)=-4/&#8730;52=-(4&#8730;52)/52