Question 973956
Given 3 consecutive even integers, the product of the first and third number is 96. What are the 3 integers?
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Use n-2, n, n+2
(n-2)*(n+2) = 96
n^2 - 4 = 96
n^2 = 100
n = -10, 10
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-12, -10, -8
8, 10, 12