Question 973968
For the mandatory pattern, there are 3 ways to choose 2 girls
AB, AC,BC
There are two ways to choose 2 boys for the one boy, D or E.

The mandatory pattern of 2 girls and 1 boy may be chosen as
ABD
ABE
ACD
ACE
BCD
BCE

If there are other patterns, the question itself has to be rewritten.

If the question is that 3 may go to market, and it doesn't matter how they are chosen, then

there are 5C3=10 total ways the 5 children may be chosen.  Some will have 3 girls, some will have 2 girls, and some will have 1 girl.

The number of patterns that allow 2 girls and 1 boy are 6.
The number of patterns that allow 3 girls are 1
The number of patterns that allow 1 girl and 2 boys are 3, both boys and each of the three girls.