Question 973760
6 ways to get a 7 (4,3),(3,4)(6,1),(1,6),(5,2),(2,5)
2 ways to get 11 (5,6),(6,5)
There are 36 possible outcomes when rolling two dice, therefore
the probability of occurring neither 7 nor 11 = 1 - ( (6/36) + (2/36) ) = 0.777777778 approx 0.78