Question 973654
A woman can bicycle 20 miles in the same time that it takes her to jog 10 miles. If she can ride 5 mph faster than she can jog, how fast can she jog?
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Jog DATA::
dist = 10 miles ; rate = x mph ; time = d/r = 10/x hrs
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Bike DATA:
dist = 20 miles ; rate = x+5 mph ; rime = 20/(x+5) hrs
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Equation:
time = time
10/x = 20/(x+5)
10x + 50 = 20x
10x = 50
x = 5 mph (jogging rate)
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Cheers,
Stan H.
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